2[4-(2+b)]=3[4(2b+5)]

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Solution for 2[4-(2+b)]=3[4(2b+5)] equation:


Simplifying
2[4 + -1(2 + b)] = 3[4(2b + 5)]
2[4 + (2 * -1 + b * -1)] = 3[4(2b + 5)]
2[4 + (-2 + -1b)] = 3[4(2b + 5)]

Combine like terms: 4 + -2 = 2
2[2 + -1b] = 3[4(2b + 5)]
[2 * 2 + -1b * 2] = 3[4(2b + 5)]
[4 + -2b] = 3[4(2b + 5)]

Reorder the terms:
4 + -2b = 3[4(5 + 2b)]
4 + -2b = 3[(5 * 4 + 2b * 4)]
4 + -2b = 3[(20 + 8b)]
4 + -2b = [20 * 3 + 8b * 3]
4 + -2b = [60 + 24b]

Solving
4 + -2b = 60 + 24b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-24b' to each side of the equation.
4 + -2b + -24b = 60 + 24b + -24b

Combine like terms: -2b + -24b = -26b
4 + -26b = 60 + 24b + -24b

Combine like terms: 24b + -24b = 0
4 + -26b = 60 + 0
4 + -26b = 60

Add '-4' to each side of the equation.
4 + -4 + -26b = 60 + -4

Combine like terms: 4 + -4 = 0
0 + -26b = 60 + -4
-26b = 60 + -4

Combine like terms: 60 + -4 = 56
-26b = 56

Divide each side by '-26'.
b = -2.153846154

Simplifying
b = -2.153846154

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